
Generate arbitrarily long sequences of consecutive numbers …
Aug 25, 2022 · The goal of this question is to find if other methods exist to generate arbitrarily long sequences of consecutive numbers without primes. I started searching for other formulas …
Minimum size of a sequence summing to $2013$ that guarantees …
Nov 25, 2025 · Minimum size of a sequence summing to $2013$ that guarantees a consecutive subset sum of $31$ (still wanted rigorous proof) Ask Question Asked 11 days ago Modified 9 …
probability - What is the expected number of times a dice has to …
Basically, on average, how many times one should roll to expect two consecutive sixes?
Consecutive composite numbers - Mathematics Stack Exchange
When I took basic number-theory course there was this exercise to find 2000 consecutive numbers. And of course it's well known that the trick to take numbers of the form $$ (n+1)!+m, …
$100$ consecutive natural numbers with no primes
Aug 6, 2018 · Additionally, Is it possible to have $1000$ consecutive natural numbers with exactly $12$ primes between them? I have an intuition that we have to form a recurrsive relation and …
Recurrence Relation for Bit String Length n with No Consecutive 0s
Oct 19, 2016 · Consider the following: Find a recurrence relation and give initial conditions for the number of bit strings of length n that do not have two consecutive 0s. I am trying to understand …
Confirming a easy proof: the product of two consecutive numbers …
Jan 12, 2021 · @Baropryl In both of your examples, you construct your consecutive numbers such that the smaller of the two is the even number. You must explicitly consider the case that …
How do I prove that for every positive integer $n$, there exist $n ...
I need help proving that for every positive integer $n$, there exist $n$ consecutive positive integers, each of which is composite. The hint that came with the ...
Proof: Sequence of n consecutive natural numbers containing no …
Proof: Sequence of n consecutive natural numbers containing no primes (Velleman P158 Thm 3.7.3) Ask Question Asked 12 years, 2 months ago Modified 11 years, 10 months ago
The product of $n$ consecutive integers is divisible by $n$ factorial
How can we prove that the product of $n$ consecutive integers is divisible by $n$ factorial? Note: In this subsequent question and the comments here the OP has clarified that he seeks a proof …